3q^2+4q-20=0

Solution for 3q^2+4q-20=0 equation:

Simplifying
3q2 + 4q + -20 = 0

Reorder the terms:
-20 + 4q + 3q2 = 0

Solving
-20 + 4q + 3q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-10 + -3q)(2 + -1q) = 0

Subproblem 1
Set the factor '(-10 + -3q)' equal to zero and attempt to solve:

Simplifying
-10 + -3q = 0

Solving
-10 + -3q = 0

Move all terms containing q to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -3q = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -3q = 0 + 10
-3q = 0 + 10

Combine like terms: 0 + 10 = 10
-3q = 10

Divide each side by '-3'.
q = -3.333333333

Simplifying
q = -3.333333333
Subproblem 2
Set the factor '(2 + -1q)' equal to zero and attempt to solve:

Simplifying
2 + -1q = 0

Solving
2 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1q = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1q = 0 + -2
-1q = 0 + -2

Combine like terms: 0 + -2 = -2
-1q = -2

Divide each side by '-1'.
q = 2

Simplifying
q = 2
Solution
q = {-3.333333333, 2}